12x^2+16x-3=(6x-1)

Solution for 12x^2+16x-3=(6x-1) equation:

12x^2+16x-3=(6x-1)

We move all terms to the left:

12x^2+16x-3-((6x-1))=0


We calculate terms in parentheses: -((6x-1)), so:

(6x-1)

We get rid of parentheses

6x-1

Back to the equation:

-(6x-1)


We get rid of parentheses

12x^2+16x-6x+1-3=0

We add all the numbers together, and all the variables

12x^2+10x-2=0

a = 12; b = 10; c = -2;
Δ = b2-4ac
Δ = 102-4·12·(-2)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*12}=\frac{-24}{24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*12}=\frac{4}{24}
=1/6
$